3(x+4)=2[x-(8-x)]

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Solution for 3(x+4)=2[x-(8-x)] equation:


Simplifying
3(x + 4) = 2[x + -1(8 + -1x)]

Reorder the terms:
3(4 + x) = 2[x + -1(8 + -1x)]
(4 * 3 + x * 3) = 2[x + -1(8 + -1x)]
(12 + 3x) = 2[x + -1(8 + -1x)]
12 + 3x = 2[x + (8 * -1 + -1x * -1)]
12 + 3x = 2[x + (-8 + 1x)]

Reorder the terms:
12 + 3x = 2[-8 + x + 1x]

Combine like terms: x + 1x = 2x
12 + 3x = 2[-8 + 2x]
12 + 3x = [-8 * 2 + 2x * 2]
12 + 3x = [-16 + 4x]

Solving
12 + 3x = -16 + 4x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x' to each side of the equation.
12 + 3x + -4x = -16 + 4x + -4x

Combine like terms: 3x + -4x = -1x
12 + -1x = -16 + 4x + -4x

Combine like terms: 4x + -4x = 0
12 + -1x = -16 + 0
12 + -1x = -16

Add '-12' to each side of the equation.
12 + -12 + -1x = -16 + -12

Combine like terms: 12 + -12 = 0
0 + -1x = -16 + -12
-1x = -16 + -12

Combine like terms: -16 + -12 = -28
-1x = -28

Divide each side by '-1'.
x = 28

Simplifying
x = 28

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